model 8 two article sold in different rates Practice Questions Answers Test with Solutions & More Shortcuts

Question : 21 [SSC MTS 2013]

A man bought a horse anda carriage for Rs.40,000. He sold the horse at a gain of 10 % and the carriage at a loss of 5%. He gained 1% on his whole transaction. The cost price of the horse was :

a) Rs.20000

b) Rs.18000

c) Rs.16000

d) Rs.15000

Answer: (c)

If the C.P. of horse be Rs.x, then

C.P. of carriage = Rs.(40000 - x) Then,

${110 × x}/100 + {(40000 - x) × 95}/100 = {40000 × 101}/100$

110x + 3800000 - 95x = 4040000

15x = 4040000 - 3800000

15x = 240000 ⇒ x = $240000/15$ = Rs.16000

Question : 22 [SSC MTS 2011]

When the price of cloth was reduced by 25%, the quantity of cloth sold increased by 20%. What was the effect on gross receipt of the shop?

a) 10% decrease

b) 10% increase

c) 5% decrease

d) 5% increase

Answer: (a)

Using Rule 7,
If a% loss and b% profit occur then, total loss/profit is $(-a + b - {ab}/100)$%
(negative sign for loss and positive sign for profit)

Required per cent effect

= $(20 - 25 - {20 × 25}/100)%$

=( - 5 - 5)% = - 10% (10% decrease)

Negative sign shows decrease

Question : 23 [SSC CGL Prelim 2004]

A man bought two goats for Rs.1008. He sold one at a loss of 20% and other at a profit of 44%. If each goat was sold for the same price, the cost price of the goat which was sold at loss, was :

a) Rs.440

b) Rs.568

c) Rs.360

d) Rs.648

Answer: (d)

If x and y be the cost price of two goats, then,

80% of x = 144% of y

$x/y = 144/80 = 9/5$

i.e., x : y = 9 : 5

Sum of the ratios = 9 + 5 = 14

Cost of first goat = Rs.$(9/14 × 1008)$ = Rs.648

Question : 24 [SSC CHSL 2013]

A shopkeeper sells an article at 15% gain. Had he sold it for Rs.18 more, he would have gained 18%. The cost price (in Rs.) of the article is

a) 350

b) 600

c) 318

d) 540

Answer: (b)

C.P. of article be Rs.x

(118 - 115)% of x = 18

${x × 3}/100 =18 ⇒ x = {18 ×100}/3$ = Rs.600

Using Rule 11,
A man sells his items at a profit/loss of x%.
If he had sold it for Rs. R more,
he would have gained/lost y%.
Then. C.P. of items = $R/{(y ± x)}$ × 100
'+' = When one is profit and other is loss.
' - ' = When both are either profit or loss.

Here, x = 15%, R= 18, y = 18%

C.P. = ${R × 100}/{y - x}$

= ${18 ×100}/{18 -15}$ = Rs.600

Question : 25 [SSC CPO S.I.2003]

A television and a refrigerator were sold for Rs.12,000 each. If the television was sold at a loss of 20% of the cost and the refrigerator at a gain of 20% of the cost, the entire transaction resulted in

a) Loss of Rs.1,200

b) Gain of Rs.1,000

c) Loss of Rs.1,000

d) No loss or gain

Answer: (c)

CP of Television = ${12,000}/80 × 100$ = Rs.15000

CP of refrigerator = ${12,000}/120 × 100$ = Rs.10,000

Total C.P. = 15000 + 10,000 = Rs.25000

SP of both = Rs.24,000

∴ Loss = 25,000 - 24,000 = Rs.1000

IMPORTANT quantitative aptitude EXERCISES

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